SOLUTION: A ladder of length 2x+1 feet is positioned against a wall such that the bottom is x−1 feet away from a wall. The distance between the floor and the top of the ladder is 2x fe

Algebra ->  Triangles -> SOLUTION: A ladder of length 2x+1 feet is positioned against a wall such that the bottom is x−1 feet away from a wall. The distance between the floor and the top of the ladder is 2x fe      Log On


   



Question 885580: A ladder of length 2x+1 feet is positioned against a wall such that the bottom is x−1 feet away from a wall. The distance between the floor and the top of the ladder is 2x feet.

Find the length, in feet, of the ladder.

The length of the ladder is ____________feet.

Assume that a right angle is formed by the wall and the floor.

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
By Pythagoras theorem
(x-1)^2+(2x)^2=(2x+1)^2
x^2-2x+1 +4x^2=4x^2+4x+1
x^2-6x=0
x(x-6)=0
x=0 OR 6


length of ladder = 6*2 = 12 feet