SOLUTION: The letters of the alphabet are written on 26 cards. Two cards are chosen at random. What is the probability that at least one of them is a consonant?

Algebra ->  Probability-and-statistics -> SOLUTION: The letters of the alphabet are written on 26 cards. Two cards are chosen at random. What is the probability that at least one of them is a consonant?      Log On


   



Question 885509: The letters of the alphabet are written on 26 cards. Two cards are chosen at random. What is the probability that at least one of them is a consonant?
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
There are 5 vowels and 21 consonants. (We are considering Y as a consonant).

There are C(26,2) = 325 possible pairs of letters.
There are C(5,2) = 10 unsuccessful pairs of letters (two vowels)
Therefore there are 325-10 = 315 successful pairs of letters.

Probability: 315 successful pairs out of 325 possible pairs or 315%2F325,
which reduces to 63%2F65.

Edwin