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There are 5 vowels and 21 consonants. (We are considering Y as a consonant).
There are C(26,2) = 325 possible pairs of letters.
There are C(5,2) = 10 unsuccessful pairs of letters (two vowels)
Therefore there are 325-10 = 315 successful pairs of letters.
Probability: 315 successful pairs out of 325 possible pairs or
,
which reduces to
.
Edwin