SOLUTION: The length of a rectangle is 5 times its width. The perimeter of the rectangle is at most 104 meters. Find the greatest possible dimensions of this rectangle?

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Question 885375: The length of a rectangle is 5 times its width. The perimeter of the rectangle is at most 104 meters. Find the greatest possible dimensions of this rectangle?
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
L length
w width
L=5w and 2w%2B2L%3C=104.
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2w%2B2%285w%29%3C=104
w%2B5w%3C=52
6w%3C=52
3w%3C=26
w%3C=26%2F3, w%3C=8%262%2F3----width
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Finding for dimension L,
Solve the other equation for w:
w=L%2F5
Substitute into the solution for w:
L%2F5%3C=26%2F3
L%3C=5%2A26%2F3
L%3C=130%2F3 or L%3C=43%261%2F3-----Length