SOLUTION: please help me to solve this equation x^2-6x-41=0 by completing the square.

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Question 885342: please help me to solve this equation x^2-6x-41=0 by completing the square.
Found 2 solutions by Tatiana_Stebko, ewatrrr:
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2-6x-41=0
%28x%5E2-6x%29-41=0
%28x%5E2-2%2Ax%2A3%2B3%5E2%29-3%5E2=41
%28x-3%29%5E2=41%2B9
%28x-3%29%5E2=50
x-3=sqrt%2850%29 or x-3=-sqrt%2850%29
x%5B1%5D=3%2Bsqrt%2850%29 , x%5B2%5D=3-sqrt%2850%29
Answer: x%5B1%5D=3%2Bsqrt%2850%29 , x%5B2%5D=3-sqrt%2850%29

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
completing the square
x^2-6x-41=0
(x-3)^2 - 9 - 41 = 0
(x-3)^2 = 50
x = 3 ± √50
x = 3 ± 5√2