Question 885201: Ravi own a plot of rectangular shape. he has fenced it with a wire of length 750 m. the length exceeds by 5m. find the length and breadth of the plot.
Answer by josgarithmetic(39617)   (Show Source):
You can put this solution on YOUR website! Typical rectangle dimensions using perimeter, problem.
w width
L length
2w+2L=750 and "the length exceeds by 5m", must really mean "The length is 5 meters more than THE WIDTH(or breadth)". This would be L=5+w.
Solve the system: 2w+2L=750 AND L=w+5.
Simplify the perimeter equation: w+L=375
Substitute for L: w+(w+5)=375
Solve that for w: 2w+5=375, 2w=370, w=185
Easily find L: L=185+5, L=190.
SUMMARY:
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Breadth, w=185 meters
Length, L=190 meters
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