SOLUTION: log_(4) x + log_(4) (x+6) = k. In this problem I need to solve for x. I also need to solve for x if k=10. I set up this problem as: 4^k = x(x+6) 4^k = x^2 + 6x x^2 +6x -

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: log_(4) x + log_(4) (x+6) = k. In this problem I need to solve for x. I also need to solve for x if k=10. I set up this problem as: 4^k = x(x+6) 4^k = x^2 + 6x x^2 +6x -       Log On


   

Question 885128: log_(4) x + log_(4) (x+6) = k.
In this problem I need to solve for x. I also need to solve for x if k=10.
I set up this problem as:
4^k = x(x+6)
4^k = x^2 + 6x
x^2 +6x - 4^k =0
Not sure where I go from here. Please help. Thank you
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Solving for x? General solution for a quadratic formula.

x=%28-6%2B-+sqrt%286%5E2-4%2A%28-4%5Ek%29%29%29%2F2
highlight%28x=%28-6%2B-+sqrt%2836%2B4%5E%28k%2B1%29%29%29%2F2%29

Assign any value you want for k and evaluate from that.