SOLUTION: A tree in front of Michelle house cast a shadow 18 ft long. If michelle is 5 ft 6 in and casts a shadow 8 feet long, how tall is the tree? Round to the nearest tenth of a foot

Algebra ->  Pythagorean-theorem -> SOLUTION: A tree in front of Michelle house cast a shadow 18 ft long. If michelle is 5 ft 6 in and casts a shadow 8 feet long, how tall is the tree? Round to the nearest tenth of a foot      Log On


   



Question 885100: A tree in front of Michelle house cast a shadow 18 ft long. If michelle is 5 ft 6 in and casts a shadow 8 feet long, how tall is the tree? Round to the nearest tenth of a foot
Answer by algebrapro18(249) About Me  (Show Source):
You can put this solution on YOUR website!
To solve this we set up a proportion between heights of things and the shadows they cast. We know that the person is 5.5 feet tall and casts an 8 foot shadow so that's our first side of our proportion. Now we want to compare that to the tree which is x feet long and casts a 18 foot shadow. So we get the following proportion:

5.5%2F8+=+x%2F18

Now we cross multiply and solve for x.

18(5.5)=8x
99 = 8x
99/8 = x
12.4 feet = x