SOLUTION: Factor: 3t^2 + t - 3 -t^3
a) take out common factors, 3 & t:
= 3 (t^2 - 1) - t (t^2 - 1)
b) rearrange
= (3 - t) (t^2 - 1)
c) difference of two squares:
= (3 - t)
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: Factor: 3t^2 + t - 3 -t^3
a) take out common factors, 3 & t:
= 3 (t^2 - 1) - t (t^2 - 1)
b) rearrange
= (3 - t) (t^2 - 1)
c) difference of two squares:
= (3 - t)
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Question 884840: Factor: 3t^2 + t - 3 -t^3
a) take out common factors, 3 & t:
= 3 (t^2 - 1) - t (t^2 - 1)
b) rearrange
= (3 - t) (t^2 - 1)
c) difference of two squares:
= (3 - t) (t - 1) (t + 1)
But the actual answer is:
= (t - 3) (1 - t) (1 + t) : Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! b) rearrange
= (3 - t) (t^2 - 1)
c) difference of two squares:
= (3 - t) (t - 1) (t + 1)
But the actual answer is:
= (t - 3) (1 - t) (1 + t)
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It's the same.
The 1st 2 terms are multiplied by -1.
