SOLUTION: A father is seven times as old as his son. In five years time he will be 4 times as old as his son. Find the product of their ages 3 years ago.

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Question 884833: A father is seven times as old as his son. In five years time he will be 4 times as old as his son. Find the product of their ages 3 years ago.
Answer by geetha_rama(94) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be the father's age and y be son's age
x+=+7%2Ay -> eq 1
After 5 yrs
x%2B5=4%2A%28y%2B5%29 -> eq 2
Solve for x and y from equation 1 and 2
Once you get x and y
do %28x-3%29%2A%28y-3%29