SOLUTION: Hello i am having some problems with loci and vertix given the equation in terms of y^2, here is the question. Q)The Vertex and Foci of curve y^2-8x-6y-23=0 is at ?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Hello i am having some problems with loci and vertix given the equation in terms of y^2, here is the question. Q)The Vertex and Foci of curve y^2-8x-6y-23=0 is at ?      Log On


   

Question 884761: Hello i am having some problems with loci and vertix given the equation in terms of y^2, here is the question.
Q)The Vertex and Foci of curve y^2-8x-6y-23=0 is at ?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The Vertex and Foci of curve y^2-8x-6y-23=0 is at ?
8x+23 = y^2-6y
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Complete the square:
y^2-6y+9 = 8x+32
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Factor:
(y-3)^2 = 8(x+4)
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Vertex at (-4,3)
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4p = 8
p = 2
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The graph is a parabola opening to the right from (-4,3)
Foci: (-4+2,3) = (-2,3)
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Cheers,
Stan H.
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