SOLUTION: Forty percent of job applicants are rejected. In a random sample of 12 applicants: what is the probability that at most 2 are rejected?

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Question 884602: Forty percent of job applicants are rejected. In a random sample of 12 applicants: what is the probability that at most 2 are rejected?
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
By formula:

P(none are rejected) + P(1 is rejected) + P(2 are rejected) =

expr%2812%21%2F%280%21%2812-0%29%21%29%29%28.4%29%5E0%281-.4%29%5E%2812-0%29%22%22%2B%22%22expr%2812%21%2F%281%21%2812-1%29%21%29%29%28.4%29%5E1%281-.4%29%5E%2812-1%29%22%22%2B%22%22expr%2812%21%2F%282%21%2812-2%29%21%29%29%28.4%29%5E2%281-.4%29%5E%2812-2%29

Or by calculator:

binomcdf(.12,.4,2)

.0834433229

Edwin