SOLUTION: A telephone perpendicular to the ground. A taut anchoring cable is 60 ft. long runs from the ground to the top of the pole. If the tangent of the angle between the ground and the c
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Question 884590: A telephone perpendicular to the ground. A taut anchoring cable is 60 ft. long runs from the ground to the top of the pole. If the tangent of the angle between the ground and the cable is 2.6, how tall is the pole? Found 2 solutions by stanbon, MathTherapy:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A telephone perpendicular to the ground. A taut anchoring cable is 60 ft. long runs from the ground to the top of the pole. If the tangent of the angle between the ground and the cable is 2.6, how tall is the pole?
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Draw the picture:
You have a right triangle with hypotenuse = 60 ft.
Let height = "h" ; Let base = "b".
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h/b = 2.6
h^2 + b^2 = 60^2
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b = h/2.6
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Substitute for "b" and solve for "h":
h^2 + (h/2.6)^2 = 60^2
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2.6^2*h^2 + h^2 = (2.6*60)^2
7.76h^2 = (2.6*60)^2
h = 56 ft
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Cheers,
Stan H.
You can put this solution on YOUR website! A telephone perpendicular to the ground. A taut anchoring cable is 60 ft. long runs from the ground to the top of the pole. If the tangent of the angle between the ground and the cable is 2.6, how tall is the pole?
Let height of pole be P
Since tan angle B = 2.6, then ≈ , so angle B =
Thus, we have:
P =
P, or height of pole = , or ≈ ft
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