SOLUTION: One week Jenna collected 50 coins. All of those were quarters mad dimes and they added up to 10.25$ let d equal the number of dimes and q equal number of quarters. How many dimes

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: One week Jenna collected 50 coins. All of those were quarters mad dimes and they added up to 10.25$ let d equal the number of dimes and q equal number of quarters. How many dimes      Log On


   

Question 884301: One week Jenna collected 50 coins.
All of those were quarters mad dimes and they added up to 10.25$ let d equal the number of dimes and q equal number of quarters. How many dimes did Jenna have?
Answer by JulietG(1812) About Me  (Show Source):
You can put this solution on YOUR website!
If Jenna had all quarters, she would have 50 * .25, or $12.50
She has only $10.25, though.
$12.50 - $10.25 = $2.25
The difference between a quarter and a dime is .15
2.25 / .15 = 15
Jenna has 15 dimes equaling $1.50
That leaves 35 quarters. .25 * 35 = $8.75
$1.50 + $8.75 = $10.25