SOLUTION: I'm being asked to rationalize the denominator: sqrt 2 ----------- ------ 1+sqrt3 answer is: -sqrt 2 + sqrt 6 ----------- ----------- --- 2

Algebra ->  Square-cubic-other-roots -> SOLUTION: I'm being asked to rationalize the denominator: sqrt 2 ----------- ------ 1+sqrt3 answer is: -sqrt 2 + sqrt 6 ----------- ----------- --- 2      Log On


   

Question 88421This question is from textbook Mathematics with Applications
: I'm being asked to rationalize the denominator:
sqrt 2
------------------
1+sqrt3
answer is:
-sqrt 2 + sqrt 6
---------------------------
2 This question is from textbook Mathematics with Applications

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
rationalize the denominator:
(sqrt 2)/(1+sqrt3)
Multiply numerator and denominator by (1-sqrt3) to get:
[sqrt2*(1-sqrt3)]/[(1+sqrt3)(1-sqrt3)]
= [sqrt2 - sqrt6]/[1 - 3]
= [sqrt2 - sqrt6]/(-2)
=========================
Cheers,
Stan H.