SOLUTION: 2x^2-15>x
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Question 884123
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2x^2-15>x
Answer by
lwsshak3(11628)
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2x^2-15>x
2x^2-x-15>0
(2x+5)(x-3)>0
critical points: 3, -5/2
number line:
<...+...-5/2...-.....3...+...>
solution:
(-∞,-5/2) U (3, ∞)