SOLUTION: Find the coordinates of a point P if P is one unit from Q(-5,-12) along the line from the origin to Q

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Question 883804: Find the coordinates of a point P if P is one unit from Q(-5,-12) along the line from the origin to Q
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!


Draw vertical lines from the known, Q, and unknown, P, points to the x-axis:



There are two similar right triangles.  The line from the origin to Q(-5,-12)
is the hypotenuse of the large right triangle.  We find it by the Pythagorean
theorem

c%5E2=a%5E2%2Bb%5E2
c%5E2=%28-5%29%5E2%2B%28-12%29%5E2
c%5E2=25%2B144
c%5E2=169
c=sqrt%28169%29
c=13

We want the hypotenuse of the smaller right triangle to be 1.
The line from the origin to P(x,y) is the hypotenuse of the small right
triangle, and we set it to equal 1.

matrix%281%2C2%2Csmall%2Chypotenuse%29%2Fmatrix%281%2C2%2Clarge%2Chypotenuse%29%22%22=%22%22

or

1%2F13%22%22=%22%22x%2F%28-5%29

13x%22%22=%22%22-5

x%22%22=%22%22-5%2F13

matrix%281%2C2%2Csmall%2Chypotenuse%29%2Fmatrix%281%2C2%2Clarge%2Chypotenuse%29%22%22=%22%22

or

1%2F13%22%22=%22%22x%2F%28-5%29

13x%22%22=%22%22-5

x%22%22=%22%22-5%2F13 

---


matrix%281%2C2%2Csmall%2Chypotenuse%29%2Fmatrix%281%2C2%2Clarge%2Chypotenuse%29%22%22=%22%22matrix%281%2C3%2Csmall%2Cvertical%2Cside%29%2Fmatrix%281%2C3%2Clarge%2Cvertical%2Cside%29

or

1%2F13%22%22=%22%22y%2F%28-12%29

13y%22%22=%22%22-12

y%22%22=%22%22-12%2F13

So the coordinates of the point that is 1 unit along the line is

P(x,y) = P%28matrix%281%2C3%2C-5%2F13%2C%22%2C%22%2C-12%2F13%29%29

Edwin