SOLUTION: Milk needs to be thinned to a ratio of 3 parts milk to 2 parts water. The milk-man has by mistake added water so that he has 8 liters of milk which is half water and half milk. Wha

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Question 883743: Milk needs to be thinned to a ratio of 3 parts milk to 2 parts water. The milk-man has by mistake added water so that he has 8 liters of milk which is half water and half milk. What must he add to make the proportions of the mixture correct?
1 liter milk
1 liter water
2 liters milk
1.5 liter milk
3 Liter milk
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
The description feels clumsy. Fraction concentration volume for volume seem more neat to use, for me, anyway.

The milk mixture needed was to be 3%2F5 milk in water. What was actually delivered was 8 liters of 2.5%2F5 milk in water. Maybe one would not like the use of rational looking numbers with non-integer part: Then we can also say,

Milk Mixture wanted: 6/10.
Milk Mixture received: 5/10.

Add some milk, v liters, to the 8 liters of less concentrated mixture.

Form this equation (as the reasoning for it is omitted):
highlight_green%28highlight_green%28%288%285%2F10%29%2Bv%29%2F%28v%2B8%29=6%2F10%29%29
and simplification should be performed
%288%281%2F2%29%2Bv%29%2F%28v%2B8%29=3%2F5
%284%2Bv%29%2F%28v%2B8%29=3%2F5
5%284%2Bv%29=3%28v%2B8%29
5v%2B20=3v%2B24
2v=4
highlight%28v=2%29 liters of milk to add.