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| Question 88371:  please I need help
 
 Answer by malakumar_kos@yahoo.com(315)
      (Show Source): 
You can put this solution on YOUR website! The length of a rectangle is 2 cm more than twice its width.  If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle
 Let the width of the rectangle be = 2x
 the length of the rectangle   = 2x+2 cms
 the perimeter of the rectangle  p = 52 cms
 p = 2(length+width)
 52 = 2(2x+2+2x)
 52/2 = 4x+2
 26-2 = 4x
 24 = 4x
 x = 24/4 = 6
 therefore length of the rectangle = 2.6+2 = 12+2 = 14 cms
 width of the rectangle = 2.6  = 12 cms
 
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