SOLUTION: The ednpoint of a diameter of a circle is (-1,6). If the center is at (2,-1), find the other endpoint of the diameter passing through (-1,6)

Algebra ->  Parallelograms -> SOLUTION: The ednpoint of a diameter of a circle is (-1,6). If the center is at (2,-1), find the other endpoint of the diameter passing through (-1,6)      Log On


   



Question 883631: The ednpoint of a diameter of a circle is (-1,6). If the center is at (2,-1), find the other endpoint of the diameter passing through (-1,6)
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Find the radius using Distance Formula for points (-1,6) and the center(2,-1)....

There is an alternative. The center and the given endpoint form a line. The other endpoint is a point on this line. Now, using Distance formula, and knowing the equation of this line, you are looking for the point this way:

D, (-1,6) to (2,-1) SAME AS D, (x,y) to (2,-1).

sqrt%28%2849%29%5E2%2B%289%29%5E2%29=sqrt%28%28x-2%29%5E2%2B%28y%2B1%29%5E2%29
sqrt%28130%29=sqrt%28x-2%29%5E2%2B%28y%2B1%29%5E2%29
130=%28x-2%29%5E2%2B%28y%2B1%29%5E2---actually this is just the equation of the circle.

The line containing given endpoint and circle center:
m=%286%2B1%29%2F%28-3%29
m=-7%2F3
y=mx+b
b=y-mx
b=-1-%28-7%2F3%29%2A2
-1-%28-14%2F3%29
14%2F3-3%2F3
b=11%2F3
-
highlight_green%28y=-%287%2F3%29x%2B11%2F3%29.

WHAT NEXT TO DO?
Substitute for y in the circle equation, simplify, and solve for x. You will get two values. The one you are looking for is the solution OTHER THAN x=-1. Now, use it to find y.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
The ednpoint of a diameter of a circle is (-1,6). If the center is at (2,-1), find the other endpoint of the diameter passing through (-1,6)

Use the midpoint formula: (%28x%5B1%5D+%2B+x%5B2%5D%29%2F2,%28y%5B1%5D+%2B+y%5B2%5D%29%2F2), equating each coordinate to the midpoint coordinates to determine
the other endpoint. Remember that you're trying to find x%5B2%5D and y%5B2%5D.
Then do a check!!
If you need a complete and detailed solution, let me know!!
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