SOLUTION: (z to the 3rd, z to the -4)all of that to the 3rd power. divided by(z to the -3rd)squared. This is what it looks like. All numerals are expoinits.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: (z to the 3rd, z to the -4)all of that to the 3rd power. divided by(z to the -3rd)squared. This is what it looks like. All numerals are expoinits.       Log On


   

Question 88363: (z to the 3rd, z to the -4)all of that to the 3rd power. divided by(z to the -3rd)squared.
This is what it looks like. All numerals are expoinits.
(z3z-4)3
_________
(z-3)2
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
(z3z-4)3
_________
(z-3)2
:
%28%28z%5E3%2Az%5E-4%29%5E3%29%2F%28%28z%5E-3%29%5E2%29 = %28%28z%5E9%2Az%5E-12%29%29%2F%28%28z%5E-6%29%29 = %28%28z%5E%289-12%29%29%29%2F%28%28z%5E-6%29%29 = %28%28z%5E-3%29%29%2F%28%28z%5E-6%29%29 = z%5E%28-3-%28-6%29%29 = z%5E%28-3%2B6%29 = z%5E3
:
The rules:
exponents on exponents, multiply exponents
multiply, add exponents
divide, subtract exponents