SOLUTION: A train is traveling at a constant rate. If it passes through a 360 meter long tunnel, it takes 16 seconds. If the train passes over a 1.2 kilometre bridge, it takes 40 seconds. Ho
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: A train is traveling at a constant rate. If it passes through a 360 meter long tunnel, it takes 16 seconds. If the train passes over a 1.2 kilometre bridge, it takes 40 seconds. Ho
Log On
Question 883601: A train is traveling at a constant rate. If it passes through a 360 meter long tunnel, it takes 16 seconds. If the train passes over a 1.2 kilometre bridge, it takes 40 seconds. How long is the train? Found 2 solutions by lwsshak3, ankor@dixie-net.com:Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! A train is traveling at a constant rate. If it passes through a 360 meter long tunnel, it takes 16 seconds. If the train passes over a 1.2 kilometre bridge, it takes 40 seconds. How long is the train?
***
let x=length of train
speed=distance/travel time (equal for both tunnel and bridge)
distance=length of train plus length of tunnel or bridge
40(360+x)=16(1200+x)
14400+40x=19200+16x
24x=4800
x=200
length of train=200 m
You can put this solution on YOUR website! A train is traveling at a constant rate.
If it passes through a 360 meter long tunnel, it takes 16 seconds.
If the train passes over a 1.2 kilometre bridge, it takes 40 seconds.
How long is the train?
:
Change 1.2 km to 1200 meters
:
Let s = the speed of the train
Let L = the length of the train
:
Write an equation for each scenario
:
Find the speed
L + 1200 = 40s
L + 360 = 16s
-----------------Subtraction eliminates L, find s
840 = 24s
s = 840/24
s = 35 km/hr is the speed of the train
:
Find L
L + 360 = 16(35)
L + 360 = 560
L = 560 - 360
L = 200 meters is the length of the train
:
;
Confirm this by finding the length using the other equation
L + 1200 = 40(35)
L = 1400 - 1200
L = 200 meters
(