Question 88351: find the partial decomposition for the rational expression. 3/2x(3x+1) 3/2x(3x+1)=?/2x+?/3x+1 the question mark represent a blank space Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! find the partial decomposition for the rational expression. 3/2x(3x+1) 3/2x(3x+1)=?/2x+?/3x+1 the question mark represent a blank space
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3/2x(3x+1) = A/2x + B/(3x+1)
= [A(3x+1)+B(2x)]/[2x(3x+1)]
Since the denominators are equal the numerators must be equal:
[3Ax+A + 2Bx] = 3
(3A+2B)x + A = 0x + 3
A = 3
Therefore:
3A+2B = 0
3*3 + 2B = 0
2B = - 9
B = -4.5
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Final Answer:
3/2x(3x+1) = 3/2x - 4.5/(3x+1)
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Cheers,
Stan H.
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