Question 883498: Katie has a collection of nickels, dimes and quarters with a total value of $3.75. There are 6 more dimes than nickels and 3 more quarters than nickels, how many of each coin does she have?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39616)   (Show Source):
You can put this solution on YOUR website! d,n,q; dimes, nickels, quarters.
0.1d+0.05n+0.25q=3.75; d=n+6; q=n+3.
More than one way to solve. First, simplify the money equation.
 ;
Next easiest is substitute for d and q in this equation, and first solve for n.
Answer by MathTherapy(10551)  (Show Source):
You can put this solution on YOUR website!
Katie has a collection of nickels, dimes and quarters with a total value of $3.75. There are 6 more dimes than nickels and 3 more quarters than nickels, how many of each coin does she have?
Let number of nickels be N
Then number of dimes = N + 6, and number of quarters = N + 3
We then have: .05(N) + .1(N + 6) + .25(N + 3) = 3.75
.05N + .1N + .6 + .25N + .75 = 3.75
.05N + .1N + .25N + .6 + .75 = 3.75
.4N + 1.35 = 3.75
.4N = 3.75 - 1.35
.4N = 2.4
N, or number of nickels =  , or  .
From this, I would think that you should be able to determine the number of dimes and quarters.
You then do a check!!
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