SOLUTION: What is the center of an ellipse 16x^2+64x+y^2-4y+4=0

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Question 883428: What is the center of an ellipse 16x^2+64x+y^2-4y+4=0
Answer by lwsshak3(11628) About Me  (Show Source):
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What is the center of an ellipse
16x^2+64x+y^2-4y+4=0
complete the square:
16(x^2+4x+4)+(y^2-4y+4)=-4+64+4
16(x+2)^2+(y-2)^2=64
(x+2)^2/4+(y-2)^2/64=1
This is an equation of an ellipse with vertical major axis.
Its standard form of equation: %28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1, (h,k)=coordinates of center
For given equation:
center: (-2,2)