SOLUTION: How do you condense 1/2[ln(x-3)+2ln(x+6)]+2lnx
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Question 883304
:
How do you condense 1/2[ln(x-3)+2ln(x+6)]+2lnx
Answer by
stanbon(75887)
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condense 1/2[ln(x-3)+2ln(x+6)]+2lnx
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= (1/2)[ln[(x-3)(x+6)^2]+ln(x^2)
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= ln[(x-3)(x+6)^2]^(1/2)*x^2]
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Cheers,
Stan H.
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