SOLUTION: It would be greatly appreciated if you are able to help me with:
Johnathan drove to the airport to pick up his friend. A rainstorm forced him to drive at an average speed of 45
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Johnathan drove to the airport to pick up his friend. A rainstorm forced him to drive at an average speed of 45
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Question 883299: It would be greatly appreciated if you are able to help me with:
Johnathan drove to the airport to pick up his friend. A rainstorm forced him to drive at an average speed of 45 mph, reaching the airport in 3 hours. He drove back home at an average speed of 55 mph. How long, to the nearest tenth of an hour, did the trip home take him?
Thanks for the help! Found 2 solutions by rfer, stanbon:Answer by rfer(16322) (Show Source):
You can put this solution on YOUR website! Johnathan drove to the airport to pick up his friend.
A rainstorm forced him to drive at an average speed of 45 mph, reaching the airport in 3 hours.
Note: distance to the airport = rate*time = 45 mph * 3 hr = 135 miles
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He drove back home at an average speed of 55 mph. How long, to the nearest tenth of an hour, did the trip home take him?
Equation:
time = distance/rate = 135 mi / 55 mph = 2.45 hrs = 2hr 33 minutes
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Cheers,
Stan H.
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