SOLUTION: Sally wants to put a border around a 4x6 inch picture. She would like the border to be twice the
area of the picture. What is the border width should Sally use (in inches)?
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-> SOLUTION: Sally wants to put a border around a 4x6 inch picture. She would like the border to be twice the
area of the picture. What is the border width should Sally use (in inches)?
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Question 883022: Sally wants to put a border around a 4x6 inch picture. She would like the border to be twice the
area of the picture. What is the border width should Sally use (in inches)?
You can put this solution on YOUR website! ally wants to put a border around a 4x6 inch picture. She would like the border to be twice the
area of the picture. What is the border width should Sally use (in inches)?
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Draw the picture::
You have a rectangle inside a rectangle.
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The inner rectangle has area 4X6 = 24 in^2
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The ourter rectangle (including the inner) has area::
(6+2x)(4+2x) = 24 + 20x + 4x^2
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The frame area = outer - inner = 4x^2 + 20x.
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Equation:
4x^2 + 20x = 2*24
x^2 + 5x - 12 = 0
x = [-5 +- sqrt(25-4*-12)]/2 = (-5+sqrt(73))/2 = 1.77 inches)
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Cheers,
Stan H.
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You can put this solution on YOUR website! The area of the picture is in2
Let = the width of the border
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Note that gets added to each
dimension when you add the border
all around
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The area of the picture plus the border is:
The area of the border is:
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Sally wants the area of the border to be in2
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Divide both sides by
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You can complete the square:
Take the square root of both sides
The border width should be 1.772 in
check:
close enough
Hope I got it