SOLUTION: A new youth center is being built in Roxbury. The perimeter of the rectangular fried us 340 yards. The length of the field us 6 yards less than triple the width. That are the dimen
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Question 882986: A new youth center is being built in Roxbury. The perimeter of the rectangular fried us 340 yards. The length of the field us 6 yards less than triple the width. That are the dimensions of the playing field? Answer by JulietG(1812) (Show Source):
You can put this solution on YOUR website! 2L + 2W = P
2L + 2W = 340
L = 3W-6
Substitute the known value of L from the bottom equation into the previous one.
2(3W-6) + 2W = 340
6W-12+2W = 340
8W-12 = 340
Add 12 to each side
8W = 352
Divide each side by 8
W = 44
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If the width is 44, the length is (3*44)-6, or 126
Perimeter fencing = 126+126+44+44, or 340
