SOLUTION: So I know this is really easy but i want to make sure I got it right on my final. What can you simplify this to: 6/sqr root 48

Algebra ->  Square-cubic-other-roots -> SOLUTION: So I know this is really easy but i want to make sure I got it right on my final. What can you simplify this to: 6/sqr root 48      Log On


   



Question 882714: So I know this is really easy but i want to make sure I got it right on my final. What can you simplify this to:
6/sqr root 48

Answer by Leaf W.(135) About Me  (Show Source):
You can put this solution on YOUR website!
6%2Fsqrt%2848%29
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Factor the number in the square root into prime numbers by trying to divide by successive prime numbers (2, 3, 5, 7, 11, 13, etc.): 48 = 2 * 24 = 2 * (2 * 12) = 2^2 * 12 = 2^2 * (2 * 6) = 2^3 * 6 = 2^3 * (2 * 3) = 2^4 * 3
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Now you have 6%2Fsqrt%282%5E4+%2A+3%29
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Try to separate the factors in the square root to the form n%5E2 whenever possible: 6%2Fsqrt%282%5E2+%2A+2%5E2+%2A+3%29
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For every n%5E2 you have, you can pull an n out of the square root since sqrt%28n%5E2%29+=+n: 6%2F%282+%2A+2+%2A+sqrt%283%29%29
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Now just multiply terms together: 6%2F%284%2Asqrt%283%29%29
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Cancel out any common factors in top and bottom; in this case, you can reduce to 3%2F%282%2Asqrt%283%29%29 by canceling out a factor of 2 from the top and bottom.
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To get the square root from the bottom, multiply the top and bottom by sqrt%283%29: 3%2Asqrt%283%29%2F%282%2A3%29+=+3%2Asqrt%283%29%2F6
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Finally, cancel out like terms on the top and bottom once again; in this case, you can take out a 3: sqrt%283%29%2F2
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Thus, your final, simplified answer is sqrt%283%29%2F2