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Question 882582: find four consecutive integers such that the sum of the first and third is 114
Answer by Leaf W.(135)   (Show Source):
You can put this solution on YOUR website! Let us call the first integer x. Since the integers are consecutive,
first integer = x
second integer = (first integer) + 1 = x + 1
third integer = (second integer) + 1 = x + 2
fourth integer = (third integer) + 1 = x + 3
since each integer will be one greater than the integer before it.
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Now we can create an equation to model the fact that "the sum of the first and third is 114":
(first integer) + (third integer) = 114
x + (x + 2) = 114
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Simplifying, we get
x + x + 2 = 114
2x + 2 = 114
2x = 112
x = 56
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Therefore, our first integer is 56, so the rest of the integers must be 57, 58, and 59. To check our answer, we can take the first integer (56) and add it to the third integer (58), and we can see that the sum is 114.
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Thus, our four consecutive integers are 56, 57, 58, and 59.
I hope this helped! =D
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