SOLUTION: HELP PLEASE...I need someone to break this down and explain this to me! The speed of a moving walkway is typically about 2.5 ft/sec. Walking on such a moving walkway, it takes Kar

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Question 882551: HELP PLEASE...I need someone to break this down and explain this to me!
The speed of a moving walkway is typically about 2.5 ft/sec. Walking on such a moving walkway, it takes Karen a total of 40 seconds to travel 50 ft with the movement of the walkway and then back again againist the movement of the walkway. What is Karen's normal walking speed?

Found 2 solutions by tajar, ankor@dixie-net.com:
Answer by tajar(5) About Me  (Show Source):
You can put this solution on YOUR website!
RULE to use: TRANSLATE A WORD PROBLEM INTO AN ALGEBRAIC EQUATION.

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The speed of a moving walkway is typically about 2.5 ft/sec.
Walking on such a moving walkway, it takes Karen a total of 40 seconds to travel 50 ft with the movement of the walkway
and then back again against the movement of the walkway.
What is Karen's normal walking speed?
:
Let w = the walking speed
then
(w+2.5) = effective speed going with the walkway
and
(s-2.5) = effective speed going against
:
Write a time equation; time = dist/speed
:
With time + against time = 40 sec
50%2F%28%28w%2B2.5%29%29 50%2F%28%28w-2.5%29%29 = 40
multiply by (w+2.5)(w-2.5), cancel the denominators and you have
50(w-2.5) + 50(w+2.5) = 40(w+2.5)(w-2.5)
50w - 125 + 50w + 125 = 40(w^2 - 6.25)
100w = 40w - 250
A quadratic equation
0 = 40w^2 - 100w - 250
simplify, divide by 10
4w^2 - 10w - 25 = 0
Use the quadratic formula to find w, only positive solution will make sense
I got a positive solution of 4.045 ft/sec for K's walking speed
;
:
You can check this out by finding the time each way should total 40 sec
50/(4.045+2.5) =
50/(4.045-2.5) =
:
:
Did explain this it to you? Let me know. ankor@att.net