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Let
the second number = x
The first number is 5 more than the second.
The first number = x+5
The third number is 4 times the first.
The third number = 4(x+5)
The sum of three numbers is 121.
x + x+5 + 4(x+5) = 121
Solve and get x = 16
The first number = x+5 = 16+5 = 21
The second number = x = 16
The third number = 4(x+5) = 4(16+5) = 4(21) = 84
Edwin