SOLUTION: Solve for all solutions for 2sinx^2+sinx-1=0

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Question 882510: Solve for all solutions for 2sinx^2+sinx-1=0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let u=sin%28x%29
2u%5E2%2Bu-1=0
%28u%2B1%29%282u-1%29=0
Two solutions:
u%2B1=0
u=-1
sin%28x%29=-1
x=%283%2F2%29pi
.
.
.
2u-1=0
2u=1
u=1%2F2
sin%28x%29=1%2F2
x=pi%2F6 and x=%285%2F6%29pi