SOLUTION: From a box containing 5 red chips and 8 blue chips, three chips are drawn in succession. Find the probability for the no. of blue chips selected if: a. sampling is done w/ replace

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Question 882453: From a box containing 5 red chips and 8 blue chips, three chips are drawn in succession. Find the probability for the no. of blue chips selected if:
a. sampling is done w/ replacement
b. w/o replacement
Found 2 solutions by ewatrrr, stanbon:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
From a box containing 5 red chips and 8 blue chips, three chips are drawn in succession
b. w/o replacement
P(0 B) = (5/13)^3
P(1 B) = (8/13)(5/13)^2
P(2 B) = (8/13)^2(5/13)^1
P(3 B) = (8/13)^3
a. sampling is done w/ replacement
P(0 B) = %285C3%29%2F%2813C3%29
P(1 B) = %288C1%29%285C2%29%2F%2813C3%29 etc
P(2 B) =
P(3 B) =

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
From a box containing 5 red chips and 8 blue chips, three chips are drawn in succession. Find the probability for the no. of blue chips selected if:
a. sampling is done w/ replacement::: (8/13)^3 = 0.2330
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b. w/o replacement:: 8C3/13C3 = 0.1959
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Cheers,
Stan H.
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