SOLUTION: Hi there,
I have to express my answer in simplest form after adding this problem. The problem reads like this: 6/3x-2 + 3/2x.
I'm not even really sure what to do, so any help
Algebra ->
Divisibility and Prime Numbers
-> SOLUTION: Hi there,
I have to express my answer in simplest form after adding this problem. The problem reads like this: 6/3x-2 + 3/2x.
I'm not even really sure what to do, so any help
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Question 88232: Hi there,
I have to express my answer in simplest form after adding this problem. The problem reads like this: 6/3x-2 + 3/2x.
I'm not even really sure what to do, so any help you can give me would be greatly appreciated!
Thank you so much!!
if we had we would have to find the LCM of both 3 and 4 --> 3*4 which we can evaluate --> 12.
We do the same with (3x-2) and 2x. Their LCM is (3x-2)*2x which we cant evaluate so we leave it like that.
Next step is to multiply both fractions by 1 (so they remain unchanged) but write the 1 as a fraction:
Algebraically we cannot do all these steps. We can do the first one:
We can multiply the numerators together and the denominators too:
And now add them together since they have the same denominator:
So that is the fractions done. The rest is just manipulation of the algebra to try to simplify it:
or perhaps multiply out the denominator:
but we tend not to do this - we like things factorised. The answer is best quoted as
