SOLUTION: If 180° < A < 270° and cos(A) = {{{-5/13}}}, solve for the value of tan(A)

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Question 882086: If 180° < A < 270° and cos(A) = -5%2F13, solve for the value of tan(A)
Answer by Edwin McCravy(20065) About Me  (Show Source):
You can put this solution on YOUR website!
If 180° < A < 270° and cos(A) = -5%2F13, solve for the value of tan(A)
Since %22180%B0%22%3CA%3C%22270%B0%22, A is in quadrant 3 we draw a right triangle in quadrant 3.  
Label the side on the x-axis as x, the vertical side y, and the hypotenuse as r.
Indicate the angle A with a red curved line rotating counter-clockwise from the
right side of the x-axis, to the terminal side, which is the hypotenuse r.



Since cos%28A%29=x%2Fr we take x to be the numerator of %28-5%29%2F13 which is -5, 
and r to be the denominator of  %28-5%29%2F13 which is 13.



Then we calculate y by the Pythagorean theorem:

x%5E2%2By%5E2=r%5E2
%28-5%29%5E2%2By%5E2=13%5E2
25%2By%5E2=169
y%5E2=144
y=+%2B-12

Since y goes down from the x-axis, we take the
negative value for y as -12




Now since the TANGENT=OPPOSITE%2FADJACENT=y%2Fx

tan%28A%29=y%2Fx=%28-12%29%2F%28-5%29=12%2F5

Edwin