SOLUTION: five times the smallest of three consecutive integers is 17 less than twice the sum of the integers

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Question 882059: five times the smallest of three consecutive integers is 17 less than twice the sum of the integers
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive integers: (x-1), x, (x+1)

4(x-1) = 2((x-1) + x + (x+1)) - 17
4x - 4 = 6x - 17
13 = 2x

The value of x is not an integer, and this cannot happen.