SOLUTION: I can't solve this problem. Please help me.
(3^x)(9^x-1) = 27^1-x
My solution:
27^2x-1 = 27^1-x
I don't know what to do next. Thank You.
Algebra ->
Exponents
-> SOLUTION: I can't solve this problem. Please help me.
(3^x)(9^x-1) = 27^1-x
My solution:
27^2x-1 = 27^1-x
I don't know what to do next. Thank You.
Log On
Question 881970: I can't solve this problem. Please help me.
(3^x)(9^x-1) = 27^1-x
My solution:
27^2x-1 = 27^1-x
I don't know what to do next. Thank You.
You can put this solution on YOUR website! (3^x)(9^x-1) = 27^1-x
(3^x)(3^2(x-1) = 3^3(1-x)
(3^x)(3^(2x-2) = 3^(3-3x)
3^(3x-2) = 3^(3-3x)
3x-2=3-3x
6x=5
x=5/6
Check:
3^(5/6)*9^(-1/6)=27^1/6
(3^(5/6))/9^(1/6)=3^(3/6)
(3^(5/6))/3^(2/6)=3^(3/6)
3^(3/6)=3^(3/6)
check ok
You can put this solution on YOUR website! I can't solve this problem. Please help me.
(3^x)(9^x-1) = 27^1-x
My solution:
27^2x-1 = 27^1-x
I don't know what to do next. Thank You.
------ Converting 9 and 27 to base 3
x + 2x - 2 = 3 - 3x ------ Bases are equal and so are their EXPONENTS
3x + 3x = 3 + 2
6x = 5
(