SOLUTION: In a Triangle abc what is the distance between the midpoint of bc and the foot of the perpendicular from a to bc, if the length of the sidesof bc,ca and ab are 5cm,7cm,6cm respecti
Algebra ->
Triangles
-> SOLUTION: In a Triangle abc what is the distance between the midpoint of bc and the foot of the perpendicular from a to bc, if the length of the sidesof bc,ca and ab are 5cm,7cm,6cm respecti
Log On
Question 881678: In a Triangle abc what is the distance between the midpoint of bc and the foot of the perpendicular from a to bc, if the length of the sidesof bc,ca and ab are 5cm,7cm,6cm respectively Answer by Edwin McCravy(20054) (Show Source):
Let M be the midpoint of BC
Let F be the foot of the perpendicular from A to BC
We find cos(B) by using the law of cosines on triangle ABC
From right triangle ABF,
Since BC=5 and M is the midpoint of BC, and BC = 5,
BM = half of 5 or
FM = BM - BF = = = = 1.3
Edwin
