SOLUTION: Find the solution to the given trig equation for 0 is less than or equal to 0 is less than or equal to 2.
sin^2 x - sinx = cos^2x
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-> SOLUTION: Find the solution to the given trig equation for 0 is less than or equal to 0 is less than or equal to 2.
sin^2 x - sinx = cos^2x
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Question 881259: Find the solution to the given trig equation for 0 is less than or equal to 0 is less than or equal to 2.
sin^2 x - sinx = cos^2x Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find the solution to the given trig equation for 0 is less than or equal to 0 is less than or equal to 2pi
sin^2 x - sinx = cos^2x
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sin^2(x) - sin(x) = 1 - sin^2(x)
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2sin^2(x) - sin(x) - 1 = 0
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(2sin(x)+1)(sin(x)-1) = 0
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sin(x) = -1/2 or sin(x) = 1
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If sin(x) = -1/2, x = (7/6)pi or x = (11/6)pi
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If sin(x) = 1, x = pi/2
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Cheers,
Stan H.
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