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Question 881102: sum of three consecutive nos is 333. find the sum of last two numbers
Answer by algebrahouse.com(1659)   (Show Source):
You can put this solution on YOUR website! x = first number
x + 1 = second number
x + 2 = third number
x + x + 1 + x + 2 = 333 {sum of the three consecutive numbers is 333}
3x + 3 = 333 {combined like terms}
3x = 330 {subtracted 3 from each side}
x = 110 {divided each side by 3}
x + 1 = 111 {substituted 110, in for x, into x + 1}
x + 2 = 112 {substituted 110, in for x, into x + 2}
sum of last two numbers
= 111 + 112
= 223
For more help from me, visit: www.algebrahouse.com
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