SOLUTION: Solve the equation 2x^3-5x^2+x+2=0 given that 2 is a zero of f(x)= 2x^2-5x^2+x+2.

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Question 881027: Solve the equation 2x^3-5x^2+x+2=0 given that 2 is a zero of f(x)= 2x^2-5x^2+x+2.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
2 is a zero; perform synthetic division to find the other polynomial factor of the function:



____2_____|____2_____-5_____1_______2
__________|
__________|__________4_____-2______-2
__________|_____________________________
quotient____________2_____-1____-1______0

That resulting quotient means x%5E2-x-1 whose roots or zeros are
x%281%2B-+sqrt%281%2B4%2A1%29%29%2F2
highlight%28x=%281%2B-+sqrt%285%29%29%2F2%29 which are the other two roots for the original equation.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the equation 2x^3-5x^2+x+2=0 given that 2 is a zero of f(x)= 2x^2-5x^2+x+2.


Factors of 2x%5E3+-+5x%5E2+%2B+x+%2B+2 are: (x - 2),(2x + 1), and (x - 1)

Therefore, solutions are: highlight_green%28highlight_green%282_and_%28-+1%2F2%29_and_1%29%29