SOLUTION: Pure acid is to be added to a 5% acid solution to obtain 95L of 75%. What amounts of each should be used? How many liters of 100% pure acid should be used to make the solution? How

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Question 880980: Pure acid is to be added to a 5% acid solution to obtain 95L of 75%. What amounts of each should be used? How many liters of 100% pure acid should be used to make the solution? How many liters of the 5% solution should be in the mixture?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Pure acid is to be added to a 5% acid solution to obtain 95L of 75%. What amounts of each should be used? How many liters of 100% pure acid should be used to make the solution? How many liters of the 5% solution should be in the mixture?
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Equation:
acid + acid
x + 0.05(95-x) = 0.75*95
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100x + 5*95 - 5x = 75*95
95x = 70*05
x = 70L (amt. of pure acid to add)
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Cheers,
Stan H.
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