SOLUTION: Write an equation for the line perpendicular to y = 5x – 12 that contains (–3, –1).

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Question 880812: Write an equation for the line perpendicular to y = 5x – 12 that contains (–3, –1).
Found 2 solutions by stanbon, Fombitz:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Write an equation for the line perpendicular to y = 5x – 12
that contains (–3, –1).
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The given equation has slope = 5
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The desired equation must have slope = -1/5
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Form: y = mx + b
Solve for "b" when m = -1/5 and y = -1 when x = -3
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-1 = (-1/5)(-3) + b
-1 = (3/5) + b
b = -8/5
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Equation:
y = (-1/5)x - (8/5)
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Cheers,
Stan H.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Perpendicular lines have slopes that are negative reciprocals.
5%2Am%5Bp%5D=-1
m%5Bp%5D=-1%2F5
Use the point slope form,
y-%28-1%29=-%281%2F5%29%28x-%28-3%29%29}
y%2B1=-%281%2F5%29x-3%2F5
y=-%281%2F5%29x-8%2F5
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