SOLUTION: one number is less than the other by five if five times the smaller number plus twice the larger is 31. then what are the numbers?

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Question 880802: one number is less than the other by five if five times the smaller number plus twice the larger is 31. then what are the numbers?
Found 2 solutions by ewatrrr, stanbon:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

x = y-5   0r y(the larger) = x+5

5x + 2(x+5) = 31

    7x = 21

     x = 3  and y = 8  3%2B5

CHECKING our answer***

15+%2B+2%2A8+=+31

Wish You the Best in your Studies.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
one number is less than the other by five if five times the smaller number plus twice the larger is 31. then what are the numbers?
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Equations:
x = y-5
5x+2y = 31
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Substitute for "x" and solve for "y":
5(y-5) + 2y = 31
7y -25 = 31
7y = 56
y = 8
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x = y-5 = 3
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Cheers,
Stan H.
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