SOLUTION: A turkey is shot up into the air from a height of 18 feet above ground level with an initial velocity of 32 feet per second, its height s (in feet) after t seconds is given by the

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Question 880719: A turkey is shot up into the air from a height of 18 feet above ground level with an initial velocity of 32 feet per second, its height s (in feet) after t seconds is given by the formula s= -16t^2 + 32 t + 18. what will the turkey reach maximum height? what is the maximum height?
Answer by lwsshak3(11628) About Me  (Show Source):
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A turkey is shot up into the air from a height of 18 feet above ground level with an initial velocity of 32 feet per second, its height s (in feet) after t seconds is given by the formula s= -16t^2 + 32 t + 18. when will the turkey reach maximum height? what is the maximum height?
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s= -16t^2 + 32 t + 18.
complete the square:
s= -16(t^2 -2t+1)+16 + 18.
s= -16(t-1)^2+34
This is an equation of a parabola that open down with vertex at (1,34)
maximum height of 34 ft is reached 1 sec after turkey is shot up in the air