SOLUTION: could you help to solve this problem and show in a equation please help A bus leaves a station at 1 P.M., traveling west at an average rate of 44 mi/h. One hour later a second b

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Question 88070: could you help to solve this problem and show in a equation please help
A bus leaves a station at 1 P.M., traveling west at an average rate of 44 mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart?
Answer by tutor_paul(519) About Me  (Show Source):
You can put this solution on YOUR website!
Start by considering what is going on at 2PM. At that time, the first bus is 44 miles away from the second bus which hasn't yet left. From that point onwards, the buses will travel at their given speeds in opposite directions. You can write the equation for how long after 2PM the buses will be 274 miles apart:
44%2B44t%2B48t=274
Where t is the time in hours.
Solving for t:
92t=230
t=2.5hours
So, that is how long after 2PM that the buses are 274 miles apart. Add that to 2PM to get the time of day (which is what they are asking):
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4:30PM
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Good Luck,
tutor_paul@yahoo.com