SOLUTION: nancy made the following statement the range of f(x) =ax +b is the set of all real numbers given that a and b are real numbers which produces a counter example to her statement

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Question 880564: nancy made the following statement the range of f(x) =ax +b is the set of all real numbers given that a and b are real numbers which produces a counter example to her statement
Answer by KMST(5328) About Me  (Show Source):
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"The range of f(x) =ax +b is the set of all real numbers given that a and b are real numbers" is almost a true statement.
Counterexample:
If a=0 the function turns into f%28x%29=b and then its range is {b}, just one real number, not all real numbers.