SOLUTION: A bowl contains 5 pieces of red candy, 6 pieces of green, and 11 pieces of blue. Two pieces are drawn and replaced back into the bowl. What is the probability of drawing from the b

Algebra ->  Probability-and-statistics -> SOLUTION: A bowl contains 5 pieces of red candy, 6 pieces of green, and 11 pieces of blue. Two pieces are drawn and replaced back into the bowl. What is the probability of drawing from the b      Log On


   

Question 880225: A bowl contains 5 pieces of red candy, 6 pieces of green, and 11 pieces of blue. Two pieces are drawn and replaced back into the bowl. What is the probability of drawing from the bowl a piece of red candy and a piece of green candy.
a. 21/242 b. 101/242 c. 15/242 d. 203/242
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Look at the possible choices.
RR=%285%2F22%29%285%2F22%29=25%2F484
RG=%285%2F22%29%286%2F22%29=30%2F484
RB=%285%2F22%29%2811%2F22%29=55%2F484
GR=%286%2F22%29%285%2F22%29=30%2F484
GG=%286%2F22%29%286%2F22%29=36%2F484
GB=%286%2F22%29%2811%2F21%29=66%2F484
BR=%2811%2F22%29%285%2F21%29=55%2F484
BG=%2811%2F22%29%286%2F21%29=66%2F484
BB=%2811%2F22%29%2811%2F21%29=121%2F484
If you add them you will find that them sum to 484%2F484 or 1.
So the probability of R then G are,
P%28RG%29=30%2F484=15%2F242