SOLUTION: The sum of three numbers is 105. The third number is 11 less than 10 times the second number. Twice the first number is 7 more than 3 times the second number. Find each number.
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Question 879925: The sum of three numbers is 105. The third number is 11 less than 10 times the second number. Twice the first number is 7 more than 3 times the second number. Find each number. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! The sum of three numbers is 105. The third number is 11 less than 10 times the second number. Twice the first number is 7 more than 3 times the second number. Find each number.
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let x=2nd number
let y=1st number
10x-11=3rd number
2y=3x+7
3x-2y=-7
..
x+y+10x-11=105
11x+y=116
3x-2y=-7
..
22x+2y=232 (mult. by 2)
3x-2y=-7
add
25x=225
x=9
10x-11=79
2y=3x+7=27+7=34
y=17
2nd number=9
1st number=17
3rd number=79
Check: 9+17+79=105
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